I am trying to figure the best (i.e. most efficient) way to get the following result:

for example

nInt=0 then x=1
iInt =1 then x=2
nInt=2 then x=4
nInt=3 then x=8
....
nInt=n then x= 2^n


Does this work?
nInt^=2;

or is it only possible with
nInt=(2^nInt);